Gregory Bard's Algebraic Cryptanalysis PDF

By Gregory Bard

ISBN-10: 0387887563

ISBN-13: 9780387887562

ISBN-10: 0387887571

ISBN-13: 9780387887579

Algebraic Cryptanalysis bridges the space among a path in cryptography, and with the ability to learn the cryptanalytic literature. This e-book is split into 3 elements: half One covers the method of turning a cipher right into a method of equations; half covers finite box linear algebra; half 3 covers the answer of Polynomial structures of Equations, with a survey of the tools utilized in perform, together with SAT-solvers and the tools of Nicolas Courtois.

The cipher Keeloq, utilized in approximately all cars with distant key-less access, is defined as a working instance, together with the manipulation of the equations to allow their answer. The circulation cipher Trivium, in addition to its versions Bivium-A and Bivium-B, and the circulate cipher family members QUAD also are analyzed as broad examples, together with summaries of numerous released attacks.

Additional subject matters include:

Analytic Combinatorics, and its program to cryptanalysis

The equicomplexity of linear algebra operations

Graph coloring

Factoring integers through the quadratic sieve, with its purposes to the cryptanalysis of RSA

Algebraic Cryptanalysis is designed for advanced-level scholars in computing device technological know-how and arithmetic as a secondary textual content or reference booklet for self-guided examine. This booklet is especially appropriate for researchers in utilized summary Algebra or Algebraic Geometry who desire to locate extra utilized issues, practitioners operating for defense and communications businesses, or intelligence agencies.

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Additional resources for Algebraic Cryptanalysis

Sample text

This should have no impact on the attack at all. Most research papers and the specification given by the company [94] includes the +Li−16 , as does our diagram; some early papers omitted it. Since the NLF is actually a cubic function this is a cubic system of equations. Substituting, we obtain 14 2 The Block Cipher Keeloq and Algebraic Attacks Li = Pi ∀i ∈ [0, 31] Li = ki−32 mod 64 + Li−32 + Li−16 + Li−23 + Li−30 +Li−1 Li−12 + Li−1 Li−30 + Li−6 Li−12 + Li−6 Li−30 ∀i ∈ [32, 559] +Li−12 Li−23 + Li−23 Li−30 + Li−1 Li−23 Li−30 +Li−1 Li−12 Li−30 + Li−1 Li−6 Li−23 + Li−1 Li−6 Li−12 Ci−528 = Li ∀i ∈ [528, 559] In other words, the above equations are to be repeated for each i in the stated intervals, and for each of µ total plaintext-ciphertext message pairs.

232 − 1 do = g−1 k (Ek (x)). (8) a. If fk (x) = x then do i. For each y ∈ P do A. Write equations assuming fk (x) = x and fk (y) = y. B. Try to solve those equations. C. If the equations yield a key k′ , see if Ek (x) = gk′ (x) and Ek (y) = gk′ (y). • If YES: Halt and report k′ is the secret key. • If NO: do nothing. ii. Insert x into P. 5: Abort. Algorithm 1: The Fixed Point Attack on Keeloq [G. 4 How far must we search? The question of how far one must search, in looking for fixed points of f (8) , before one can find 2 fixed points of f , is crucial for determining the running time of the attack.

9 on Page 16, both in terms of number of equations and in terms of number of variables. 7 depending on the algorithm used. Of course, solving a polynomial system of equations is far harder than solving a linear system, so the speed-up is expected to be very much larger than that. And so, our second objective, which is speed, is accomplished. This leaves us with the following attack: • Search the code-book for fixed points of f (8) . • Find two fixed points of f by trying pairs of fixed points of f (8) .

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